F(x)=5x^2+1x=-3

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Solution for F(x)=5x^2+1x=-3 equation: 



(F)=5F^2+1F=-3

We move all terms to the left:

(F)-(5F^2+1F)=0

We get rid of parentheses

-5F^2+F-1F=0

We add all the numbers together, and all the variables

-5F^2=0

a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$F=\frac{-b}{2a}=\frac{0}{-10}=0$

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